The Joint Entrance Examination (JEE Advanced) 2018, which is conducted for admission to the Bachelor's, Integrated Master's and Dual Degree programmes (entry at the 10+2 level) in all the IITs, will be held on May 20, 2018. It will be conducted in fully computer based test mode. The Indian Institute of Technology Kanpur (IIT Kanpur) has declared the eligibility criteria for the exam and it is also expected that more students will be able to appear for the exam.

As per a statement declared by IIT Kanpur, top 224,000 candidates will be chosen to appear for JEE (Advanced) next year based on the category-wise distribution of candidates released on the website.

It also told that the total number of candidates can be slightly greater than 2,24,000 in the presence of "tied" ranks/scores in any category.

The percentages of various categories of candidates to be shortlisted are :

• OBC-NCL : 27%
• SC : 15%
• ST : 7.5%
• Open to all : 50.5%

Within each of these 4 categories, 5% horizontal reservation is available for PwD candidates.

Age limit :

Candidates should have been born on or after October 1, 1993. 5 years relaxation is given to SC, ST and PwD candidates, i.e., these candidates should have been born on or after October 1, 1988.

Attempts :

A candidate can attempt JEE (Advanced) a maximum of 2 times in consecutive years.

Appearance in Class XII (or equivalent) exam :

A candidate should have appeared for the Class XII (or equivalent) exam for the first time in either 2017 or 2018.

The decision by the Joint Admission Board (JAB) was taken recently keeping in mind the increasing intake of all 22 IITs and the Indian School of Mines (ISM) in Dhanbad. According to an HT report, of the 10,998 seats in the 23 IITs, the number of vacancies after 7 rounds of counselling stood at 121 this year, up from 96 last year, and 50 in 2015, and 3 in 2014.

Source: http://indiatoday.intoday.in/education/